Algebra of vectors
Zero vector, opposite vectors
\[
\vec{r} + \vec{r\,}' = 0 \quad \Longleftrightarrow \quad \vec{r\,}' = - \vec{r}
\]
Can add vectors in any order
\[
\vec{W} + \vec{T} + \vec{F} = \left(\vec{W} + \vec{T}\right) + \vec{F} =
\vec{W} + \left(\vec{T} + \vec{F}\right)
\]
Vector components
-
resolve $\vec{T}$ into component vectors $\vec{T}_\mbox{h}$
and $\vec{T}_\mbox{v}$
\[
\vec{T} = \vec{T}_\mbox{h} + \vec{T}_\mbox{v}
\]
-
unit vectors $\hat{x}$, $\hat{y}$ define the reference frame
-
scalar components $r_x$, $r_y$ of vector $\vec{r}=r\angle \theta $
$$ \vec{r} = r_x \> \hat{x} + r_y \> \hat{y} $$
-
from $r\angle\theta$ to $r_x$, $r_y$ : measure $\theta$ counterclockwise from $+x$ direction
\[
\left\{ \begin{array}{lll} r_x = r \> \cos\theta \\
r_y = r \> \sin\theta \end{array} \right.
\]
-
from $r_x$, $r_y$ to $r\angle\theta$ : Pythagorean theorem
\[ \left\{ \begin{array}{l} r= \sqrt{ \> r_x^2 + r_y^2} \\
\theta = \arctan{{r_y}\over{r_x}} \end{array} \right.
\]
Relating vectors and their components
two vectors are equal, $\vec{r} = \vec{r\,}'$
$$ \Updownarrow $$
their magnitudes are equal, $r = r'$ and
their directions are the same, $\theta = \theta '$
$$ \Updownarrow $$
their components are equal:
\[
\left\{ \begin{array}{lll} r_x = r \> \cos\theta = r'_x = r'\> \cos\theta' \\
r_y = r \> \sin\theta = r'_y = r'\> \sin\theta' \end{array} \right.
\]
|